eigenvalues of the induced graphon converge pointwise to the eigenvalues of the limit

[[concept]]
Theorem

Let {Gn} be a convergent graph sequence with limit graphon W. Then

limn→∞λj(An)n=λj(W)=limn→∞λj(TWn)

ie, the eigenvalues of the induced graphon converge to the eigenvalues of the limit.

Where

Proof

Wn(u,v)=∑i,j=1n[An]ij1(u∈Ii)1(v∈Ij)An=VnΛnVn∗

Thus

TWnφ(v)=∫01Wn(u,v)φ(u)du=λφ(v)=∫01∑i,j=1n[An]ij1(u∈Ii)1(v∈Ij)φ(u)du=λφ(v)=1(v∈Ij)∫01∑i,j=1n[An]ij1(u∈Ii)φ(u)du=λφ(v)⟹=∑i,j=1n[An]ij∫011(u∈Ii)φ(u)du=λφ(v∈Ij)

LHS is a constant for each v∈Ij. This means that φ is a step function φ(v∈Ij)=xj. Thus, we can rewrite the last line as

λxj=∑i=1n[An]ijxi1n

since for each i we have φ(u)={xi,xi∈Ii0,otherwise . The above is just a matrix multiplication, so we get

⟹λx=1nAnx⟹λj(TWn)=λj(An)n∀j

For convergence, this means that

(1)t(ck,Gn)=∑i=1nλik(2)t(ck,Gn)→t~(ck,W)

where

(the full proof involves writing out the expressions for (1) and showing (2) that the elements in the sum converge pointwise. We do not show this for this class.)

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